What is the default metric used by eigrp router
Minimum bandwidth on the path and the total delay
How bandwidth and delay are determined
Determined from values configured on the interfaces of
router in the path to the destination network
How many paths router one has to reach network A
It has two path
Through router four and through router three
What is the bandwidth and delay configured through router
four
Minimum bandwidth 56
Total delay 2000
What is the minimum bandwidth and delay configured through
router three
Minimum bandwidth 128
Total delay 1000
Which path will be chosen by router one
Path with lowest metric
Which formula used by eigrp to scale bandwidth
Bandwidth =
(10000000/bandwidth(i)) * 256
Where bandwidth(i) least bandwidth to destination and
represented in kilobits
Which formula used by eigrp to scale delay
Delay = delay(i) * 256
Where delay(i) is the sum of the delays configured on the
interfaces to destination and represented in ten microseconds
How delay are represented in show ip eigrp topology or show
interface command
In microseconds
We need divide delay by 10 before we use it on the formula
Which formula used by eigrp to scale total metric to
destination network
Metric = ([K1 * bandwidth + (K2 * bandwidth) / (256 - load)
+ K3 * delay] * [K5 / (reliability + K4)]) * 256
What is the importance of using k value
Must be used carefully
Mismatch k values prevent neighbor relationship from being
built and will not converge network
What would be the formula if k5 = 0
Metric = ([k1 * bandwidth + (k2 * bandwidth)/(256 - load) +
k3 * delay]) * 256.
What is the default k values
The default values for K are:
K1 = 1
K2 = 0
K3 = 1
K4 = 0
K5 = 0
What would be the formula with default k values
Metric = bandwidth + delay
Does cisco routers uses floating point number
No
In the above network, what would be the total cost through
router four
Minimum bandwidth = 56k
Total delay = 100 + 100 + 2000 = 2200
[(10000000/56) + 2200] x 256 = (178571 + 2200) x 256 =
180771 x 256 = 46277376
What would be the total cost through router three
Minimum bandwidth = 128k
Total delay = 100 + 100 + 1000 = 1200
Bandwidth = [(10000000/128) + 1200] x 256 = (78125 + 1200) x
256 = 79325 x 256 = 20307200
Metric = 20307200 +
1200
Which path will be chosen by router one to reach network A
Router one will choose path through router three
Path through router three has lowest metric
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